bio::meta::weakly_assignable_from Concept Reference

Resolves to std::is_assignable_v<t>. More...

#include <bio/meta/concept/core_language.hpp>

Concept definition

template<typename t, typename u>
concept bio::meta::weakly_assignable_from =  std::is_assignable_v<t, u>

Detailed Description

Resolves to std::is_assignable_v<t>.

See also

https://en.cppreference.com/w/cpp/types/is_assignable

Note that this requires less than std::assignable_from, it simply tests if the expression std::declval<T>() = std::declval<U>() is well-formed.